Thursday, 10 January 2013

Network and communication sample questions

Sample Questons

June 2012

11. X.25 is ________ Network.
(A) Connection Oriented Network
(B) Connection Less Network
(C) Either Connection Oriented or
Connection Less
(D) Neither Connection Oriented nor
Connection Less
Answer: A

june 2008

26. The ATM cells ------ byte long
(a)48 (b)53 (c) 64 (d)69

Answer: b
1. Which of the following network acess standard is used for connecting station to a packet switched network?
A. X.3  B. X.21  C. X.25  D. X.75

Answer: C

2. How many layers covered in X.25 standards?
a.3   b.4  c.2 d.7

Answer: A

3. RS-232 RS-449 RS-530  V-24 and X-21 are examples of
a. Standard for various type of transmission channels 
b. standards for interface between terminals and modems  
c. methods for error detection and correction 
d. Standard for end to end performance of data communication system
Answer: B

4. An example of network layer protocol is
a. Internet protocol
b. X-25 packet level protocol
c. source routing and domain naming 
d. all of the above

Answer: D

5. Standard of electronic Industries association of America . what do the letter RS stands for
a. Recognized standard 
b. Random sequence  
c. Recommended standard 
d. Registered source
Answer: C

6. The interface between the computer or terminal and the modem is an example of
a. Physical layer protocol 
b. Data link layer protocol 
c. Network layer protocol
d. Transport layer protocol
Answer: A

7. X.21 is
a. a method of determining which device has access to transmission medium at any time
b. a method access control technique for multiple access transmission media
c. a very common bit oriented data link protocol issued by ISO
d. network access standard for connecting stations to a circuit switched network
Answer: D

8. The address field of a Frame Relay frame is 1011000000010111. What is the DLCI
(in decimal)?

9. The address field of a Frame Relay frame is 101100000101001

10. Find the DLCI value if the first 3 bytes received is 7C 74 El in hexadecimal.

 Answers


8. We first need to look at the EA bits. In each byte, the EA bit is the last bit (the eight bit from the left). If EA bit is 0, the address ends at the current byte; if it 1, the address continues to the next byte.
Address = 10110000 00010111
The first EA bit is 0 and the second is 1. This means that the address is only two bytes (no address extension). DLCI is only 10 bits, bits 1 to 6 and 9 to 12 (from left).
Address →10110000 00010111
DLCI →1011000001 705

10. We first need to look at the EA bits. In each byte, the EA bit is the last bit (the eight bit from the left). If the EA bit is 0, the address ends at the current byte; if it 1, the address continues to the next byte.
Address =  0x7C74E1 = 01111100 01110100 11100001
The first two EA bit are 0s and the last is 1. This means that the address is three bytes (address extension). DLCI is 16 bits, bits 1 to 6, 9 to 12, and 17 to 22.
Address =  01111100 01110100 111000
DLCI = 0111110111111000  =  32248



1 comment:

  1. Ans Explanation: The extended address (EA) bit indicates whether the current byte is the final byte of the address. When it is set to 0, then the next octet contains the rest of the address; otherwise(1), it indicates the last field of the address. This bit can be used to represent extended addressing.

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